3[z-(9z+13)+5]=2(z+1)

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Solution for 3[z-(9z+13)+5]=2(z+1) equation:


Simplifying
3[z + -1(9z + 13) + 5] = 2(z + 1)

Reorder the terms:
3[z + -1(13 + 9z) + 5] = 2(z + 1)
3[z + (13 * -1 + 9z * -1) + 5] = 2(z + 1)
3[z + (-13 + -9z) + 5] = 2(z + 1)

Reorder the terms:
3[-13 + 5 + z + -9z] = 2(z + 1)

Combine like terms: -13 + 5 = -8
3[-8 + z + -9z] = 2(z + 1)

Combine like terms: z + -9z = -8z
3[-8 + -8z] = 2(z + 1)
[-8 * 3 + -8z * 3] = 2(z + 1)
[-24 + -24z] = 2(z + 1)

Reorder the terms:
-24 + -24z = 2(1 + z)
-24 + -24z = (1 * 2 + z * 2)
-24 + -24z = (2 + 2z)

Solving
-24 + -24z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-24 + -24z + -2z = 2 + 2z + -2z

Combine like terms: -24z + -2z = -26z
-24 + -26z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-24 + -26z = 2 + 0
-24 + -26z = 2

Add '24' to each side of the equation.
-24 + 24 + -26z = 2 + 24

Combine like terms: -24 + 24 = 0
0 + -26z = 2 + 24
-26z = 2 + 24

Combine like terms: 2 + 24 = 26
-26z = 26

Divide each side by '-26'.
z = -1

Simplifying
z = -1

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